Given a non-empty array of integers, every element appears twice except for one. Find that single one.
Input : Array = [7,1,2,3,1,2,3]
Output : 7
#use for loop if necessary Arr = list(map(int,input('Enter the array elements : ').split(' '))) temp=0 for i in range(len(Arr)): temp=temp^Arr[i] # using Xor operator print('Minimum - ',temp)
Input_1:
Enter the array elements : 1 2 3 7 1 2 3
Output:
Minimum – 7
Input_2:
Enter the array elements : 7 8 9 6 7 8 9
Output:
Minimum – 6
Input_3:
Enter the array elements : 20 25 30 20 30
Output:
Minimum – 25
Input_4:
Enter the array elements : 9 6 3 2 9 3 6
Output:
Minimum – 2
Input_5:
Enter the array elements : 7 4 1 2 2 4 7
Output:
Minimum – 1
ILLUSTRATION OF THE OUTPUT
![](http://www.fcukthecode.com/wp-content/uploads/2021/08/Screenshot-from-2021-08-12-16-39-21.png)
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