Given binary array, find count of maximum number of consecutive 1’s present in the array.
Input : arr[] = {1, 1, 0, 0, 1, 0, 1, 0, 1, 1, 1, 1}
Output : 4
Input : arr[] = {0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1}
Output : 1
def maxibin(arr): temp=0 count=0 for i in range(len(arr)): if arr[i]==0 : count=0 else: count+=1 temp=max(count,temp) return temp Arry=list(map(int,input('arr[] : ').split(' '))) print(maxibin(Arry))
Input_1:
arr[ ] : 1 1 0 0 1 0 1 0 1 1 1 1
Output:
4
Input_2:
arr[ ] : 0 0 1 0 1 0 1 0 1 0 1
Output
1
Input_3:
arr[ ] : 1 1 1 0 1 0 1 0 1 1 1 0
Output:
3
Input_4:
arr[ ] : 1 1 1 0 1 1 0 1 1 1 1 0 1 1 1
Output:
4
Illustration of the Output:
![](http://www.fcukthecode.com/wp-content/uploads/2021/12/Screenshot-from-2021-12-08-22-18-16.png)
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